Hours ≈ mAh ÷ mA

Capacity in mAh and average load in mA—ideal hours before cutoff (not including efficiency loss).

FAQ

Is runtime simply capacity ÷ current?

Yes for this page: hours = Ah ÷ A (capacity in amp‑hours, load current in amps), plus a minutes line labeled as ideal. Peukert effect, cutoff voltage, temperature, and efficiency are not modeled.

Does the decimal separator matter?

This calculator uses plain decimal numbers. If a result looks wrong, check whether you used a comma instead of a dot (or vice versa) where the field expects one.